In the prime factorization of 132, if it is 2 times 2 times 3 times X, what is the value of X?

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Multiple Choice

In the prime factorization of 132, if it is 2 times 2 times 3 times X, what is the value of X?

Explanation:
To find the value of X in the prime factorization of 132, let's start with the complete factorization of 132. First, we can divide 132 by the smallest prime number, which is 2. This gives us: 132 ÷ 2 = 66. We can apply the division by 2 again, since 66 is also even: 66 ÷ 2 = 33. Now, we are left with 33, which is no longer divisible by 2. The next smallest prime number is 3: 33 ÷ 3 = 11. At this point, we have 11 remaining, which is also a prime number. Thus, the complete prime factorization of 132 can be expressed as: 2 × 2 × 3 × 11. In the context of the question, we see that 2 times 2 times 3 times X must match this factorization. From our complete breakdown, it is clear that X corresponds to the leftover prime factor of 11. Therefore, the value of X is 11.

To find the value of X in the prime factorization of 132, let's start with the complete factorization of 132.

First, we can divide 132 by the smallest prime number, which is 2. This gives us:

132 ÷ 2 = 66.

We can apply the division by 2 again, since 66 is also even:

66 ÷ 2 = 33.

Now, we are left with 33, which is no longer divisible by 2. The next smallest prime number is 3:

33 ÷ 3 = 11.

At this point, we have 11 remaining, which is also a prime number. Thus, the complete prime factorization of 132 can be expressed as:

2 × 2 × 3 × 11.

In the context of the question, we see that 2 times 2 times 3 times X must match this factorization. From our complete breakdown, it is clear that X corresponds to the leftover prime factor of 11.

Therefore, the value of X is 11.

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